diff --git a/tools/rnblight/Foo.kt b/tools/rnblight/Foo.kt
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+++ b/tools/rnblight/Foo.kt
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+/**
+ * @author Holger Brandl
+ */
+
+class Foo
\ No newline at end of file
diff --git a/tools/rnblight/example.Rmd b/tools/rnblight/example.Rmd
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+Frequency tests
+================
+
+* Example: Prop of dieting woman higher than for men?
+
+![](.example_images/fisher_example.png)
+
+```
+?fisher.test
+```
+
+
+Proportion Tests
+================
+
+```{r}
+prop.test(x=333, n=1022, conf.level=0.98)
+
+prop.test(x=333, n=1022)
+```
+
+From
+http://stats.stackexchange.com/questions/60073/confidence-interval-for-difference-between-proportions
+
+The sample size is 34, of which 19 are females and 15 are males. Therefore, the difference in proportions is 0.1176471.
+
+```{r}
+19/34 - 15/34
+prop.test(x=c(19,15), n=c(34,34), correct=FALSE)
+
+## also works for single proportion
+#prop.test(x=c(19), n=c(34), correct=FALSE)
+#prop.test(x=c(19,15,20), n=c(34,34,34), correct=FALSE)
+
+```
+Also see <http://stat.ethz.ch/R-manual/R-devel/library/stats/html/prop.test.html>
+
+Nice math introhttps://onlinecourses.science.psu.edu/statprogram/node/164 with t-statistc
+
+
+
+Confidence around proportions
+-----------------------------
+
+Formula:
+ > If the samples size n and population proportion p satisfy the condition that np ≥ 5 and n(1 − p) ≥ 5, than the end points of the interval estimate at (1 − α) confidence level is defined in terms of the sample proportion as follows.
+ ![](.example_images/prop_ci.png)
+
+CI math is detailed out under http://www.statisticslectures.com/topics/ciproportions/
+
+```{r}
+prop.test(x=333, n=1022, conf.level=0.98)
+plot(1:10)
+plot(1:10)
+prop.test(x=333, n=1022)
+plot(1:10)
+```
+
diff --git a/tools/rnblight/example_filt.md b/tools/rnblight/example_filt.md
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index 0000000000000000000000000000000000000000..de5210d5600c4cbde41c8c6e97de7286e94d5eb2
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+++ b/tools/rnblight/example_filt.md
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+Frequency tests
+================
+
+* Example: Prop of dieting woman higher than for men?
+
+![](.example_images/fisher_example.png)
+
+```
+?fisher.test
+```
+
+
+Proportion Tests
+================
+
+
+```r
+prop.test(x=333, n=1022, conf.level=0.98)
+```
+
+
+```r
+prop.test(x=333, n=1022)
+```
+
+
+From
+http://stats.stackexchange.com/questions/60073/confidence-interval-for-difference-between-proportions
+
+The sample size is 34, of which 19 are females and 15 are males. Therefore, the difference in proportions is 0.1176471.
+
+
+```r
+19/34 - 15/34
+```
+
+
+```r
+prop.test(x=c(19,15), n=c(34,34), correct=FALSE)
+```
+
+
+```r
+## also works for single proportion
+#prop.test(x=c(19), n=c(34), correct=FALSE)
+#prop.test(x=c(19,15,20), n=c(34,34,34), correct=FALSE)
+```
+Also see <http://stat.ethz.ch/R-manual/R-devel/library/stats/html/prop.test.html>
+
+Nice math introhttps://onlinecourses.science.psu.edu/statprogram/node/164 with t-statistc
+
+
+
+Confidence around proportions
+-----------------------------
+
+Formula:
+ > If the samples size n and population proportion p satisfy the condition that np ≥ 5 and n(1 − p) ≥ 5, than the end points of the interval estimate at (1 − α) confidence level is defined in terms of the sample proportion as follows.
+
+CI math is detailed out under http://www.statisticslectures.com/topics/ciproportions/
+
+
+```r
+prop.test(x=333, n=1022, conf.level=0.98)
+```
+
+
+```r
+plot(1:10)
+plot(1:10)
+```
+
+
+```r
+prop.test(x=333, n=1022)
+```
+
+
+```r
+plot(1:10)
+```
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